WebSolution 1 (displaying the year and the money earned): The result is: Solution 2 (displaying the complete date, the year, and the money earned in the corresponding year): SELECT transaction_date AS transaction_date, EXTRACT (year FROM transaction_date) AS year, SUM(money) OVER (PARTITION BY EXTRACT (year FROM transaction_date)) AS … WebWHERE HIRE_DATE < 'today' As you can see, the same rule applies for CURRENT_DATE, and you can use a special value 'today', to get the current value. Beside that, you might also find 'tomorrow' and 'yesterday' useful. The reason behind all this is that statements should be atomic, so CURRENT_DATE and CURRENT_TIMESTAMP provide consistency.
How to get the Firebird server date and time?
WebExtraction from a date or time value is also defined in SQL 92 EXTRACT ( FROM ) Where is one of YEAR, MONTH, DAY, HOUR, MINUTE, SECOND For instance: SELECT name FROM operations WHERE EXTRACT (HOUR FROM start_time) < 7; Reference: SQL, Oct 97, Section 6.14, page 155 Predefined Functional Operators: WebDec 4, 2007 · If you need portions (day, month, year) of a date/time, then use the EXTRACT function. E.g.: EXTRACT (DAY FROM ) EXTRACT (MONTH FROM ) EXTRACT (YEAR FROM ) -- Best Regards, Thomas Steinmaurer LogManager Series - Logging/Auditing Suites supporting geoffrey simmons
Using CAST(..) with Date/Time Types - Firebird - Wisdom Jobs
WebSyntax: CAST ( expression AS datatype) Shorthand syntax: Alternative syntax, supported only when casting a string literal to a DATE, TIME or TIMESTAMP : datatype 'date/timestring' This syntax was already available in InterBase, but was never properly documented. Examples: A full-syntax cast: WebIt seems SQL calls varies a lot, and cannot find how to do this in Firebird, where SQL dialect is 3. There's a table called TICKETS. This table has INSERT_TIME which is TIMESTAMP. How do I select all the tickets which has insert time year = 2016? WebMay 30, 2024 · There are several ways to return the year from a date in SQL Server. Here are three (or is it four?). YEAR () The most obvious method is to use the YEAR () function. This function returns an integer with the year portion of the specified date. DECLARE @date date = '2024-10-25'; SELECT YEAR (@date); Result: 2024 DATEPART () chris miami heat