Find three numbers in gp whose sum is 13
WebMay 9, 2024 · The question is: Find all Arithmetic progression of natural numbers starting with $3$ whose sum is a $3$ digit number whose digits are in non constant GP. I tried that the sum could be $124, 421, 139, 931, 469, 964, 248, 842 but then $ 3+ (n-1)d$ equals the above numbers would give lot of boundary conditions. Not sure how to go further. Pl help. WebHow to find three numbers in GP whose sum is 13 and (Show Source):. You can put this solution on YOUR website! 1, 3, and 9. If the sum of the three numbers and the sum of …
Find three numbers in gp whose sum is 13
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WebThe sum of three numbers in geometric progression is 31 and sum of their squares is 651.Find the numbers. Ask Question Asked 6 years, 2 months ago. Modified 6 years, 2 months ago. Viewed 16k times ... Finding first three terms of a GP whose sum and sum of squares is given? 0. WebMar 6, 2024 · Find three numbers in GP whose sum is 13 and the sum of whose squares is 91. Asked by asingh292002 06 Mar, 2024, 03:05: PM Expert Answer Please …
Web[Solved] Find three numbers in GP whose sum is 13 and the Find three terms of G.P. whose sum is 13 and sum of their whole squares is 91. Let the three terms of a G.P. be … Web1/r + r + 1 = 13/3 Now , we will subtract 1 both sides 1/r + r + 1 - 1 = 13/3 - 1 ... Find three numbers in G.P. whose product is 729 and the sum of their products in pairs is 819. ... then find the numbers. Q. If the product of three numbers in GP is 216 and the sum of their products in pairs is 156, find the numbers.
WebAnswer by mananth (16132) ( Show Source ): You can put this solution on YOUR website! Let the numbers be a/r, a,ar a/r + a +r =19 a/r*a*ar=219 a^3= 216 a=6 a+ar+ar^2 = 19r 6+6r+6r^2=19r 6r^2-13r+6 =0 6r^2-9r-4r+6=0 3r (2r-3)-2 (2r-3)=0 (2r-3) (3r-2)=0 r=3/2 OR r=2/3 plug a & r when r=3/2 a/r = 6/ (3/2) =4 a=6 ar = 9 4,6,9 OR r=2/3 a/r = 6/ (2/3) =9 WebJun 12, 2024 · Best answer Let the three numbers be a/r, a, ar So, according to the question a/r + a + ar = 38 … equation (1) a/r × a × ar = 1728 … equation (2) From equation (2) we get, a3 = 1728 a = 12. From equation (1) we get, (a + ar + ar2)/r = 38 a + ar + ar2 = 38r … equation (3) Substituting a = 12 in equation (3) we get 12 + 12r + 12r2 = 38r
WebJun 28, 2024 · Find the three numbers in GP whose sum is 13 and the sum of whose squares is 91. class-11 Please log in or register to answer this question. 1 Answer 0 …
WebMar 30, 2024 · Answer Verified 301.8k + views Hint: Let the four numbers in G.P. be a r 3, a r, a r, a r 3. Multiply these and equate with 4096 to get a = 8. Now, take their sum to get 8 r 3 + 8 r + 8 r + 8 r 3 = 85. Next, let z = r + 1 r. Substitute this in the previous equation to get 8 z 3 − 16 z − 85 = 0. Now, substitute t = 2 z to get t 3 − 8 t − 85 = 0. healthy choice frozen dinners at walmartWebFind three terms of G.P. whose sum is 13 and sum of their whole squares is 91. Let the three terms of a G.P. be a, ar, ar2. Hence, the terms of this G.P. healthy choice frozen meals walmartWeb[Solved] Find three numbers in GP whose sum is 13 and the. Watch the complete video at: three numbers in G.P. whose sum is 13 and the sum of whose squares is. Deal … motor serv uk shirleyWebSep 19, 2024 · Find three numbers in G.P. whose sum is 13 and the sum of whose squares is 91. - YouTube 0:00 / 7:40 #SEQUENCESANDSERIES #rdsharma #doubtnut Find three … healthy choice frozen meals power bowlsWebSolution. Solution:- (C) 4, 12, 36. Let the three numbers be a,ar,ar2 a, a r, a r 2. Given that sum is 52. ∴ a+ar+ar2 = 52 ∴ a + a r + a r 2 = 52. ⇒ a(1+r+r2) = 52 (1) ⇒ a ( 1 + r + r 2) = 52 ( 1) Sum of product of numbers in pairs is 624. ∴ a.ar +ar.ar2+ar2.a = 624 ∴ a. a r + a r. a r 2 + a r 2. a = 624. ⇒ a2r(1+r2+r) = 624 ⇒ a ... healthy choice frozen power bowlsWebFind three numbers in G.P. whose sum is 13 and Solution : Let the required numbers be `a/r, a` and `ar`. Then, br `a/r+a+ar=13`(i) br and `a^(2)/r^(2)+a^(2)+a^(2)r^(2)=91`. healthy choice frozen meals recallWebSolution Let the terms of the the given G.P. be a and ar a r, a and ar . Then, product of the G.P. = 1728 ⇒ a 3 = 1728 ⇒ a = 12 Similarly, sum of the G.P. = 38 ⇒ a r + a + a r = 38 Substituting the value of a 12 r + 12 + 12 r = 38 ⇒ 12 r 2 + 12 r + 12 = 38 r ⇒ 12 r 2 − 26 r + 12 = 0 ⇒ 2 ( 6 r 2 − 13 r + 6) = 0 ⇒ 6 r 2 − 13 r + 6 = 0 healthy choice frozen dinners list